Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide Solution for RD Sharma Class 12 Chapter 6 Adjoint and Inverse of a Matrix Exercise 6.1 Question 7 subquestion (i)

Provide Solution for RD Sharma Class 12 Chapter 6 Adjoint and Inverse of a Matrix Exercise 6.1 Question 7 subquestion (i)

Answers (1)

best_answer

Answer:

A^{-1}=\left[\begin{array}{cc} \cos \theta &- \sin \theta \\ \sin \theta & \cos \theta \end{array}\right]

Hint:

Here, we use basic concept of inverse

Given:

  A=\left[\begin{array}{cc} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{array}\right]

Solution:

A^{-1}=\frac{1}{|A|} \times A d j(A)

Let’s find  \left | A \right |

|A|=\cos ^{2} \theta+\sin ^{2} \theta=1

So,

A^{-1}=\left[\begin{array}{cc} \cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{array}\right]

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CIC asks CBSE to disclose tender process for exam answer sheet procurement under RTI Act
anam-khan

CBSE 10th Second Board Result 2026 LIVE: Class 10 session 2 scores soon at cbse.gov.in; passing marks
anam-khan

Delhi HC refuses to direct reopening of CBSE class 12 re-evaluation portal

Latest Question