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Provide solution for RD Sharma maths Class 12 Chapter Functions Exercise 2.3 Question 12 maths text book solution.

Answers (1)

Answer :

f \circ f(x)=\left\{\begin{array}{ll} 2+x ; & 0 \leq x \leq 1 \\ 2-x ; & 1<x \leq 2 \\ 4-x ; & 2<x \leq 3 \end{array}\right.

Hint : Range of f=[0,3] \subseteq \text { domain of } f.

Given : Given that  f(x)=\left\{\begin{array}{cc} 1+x ; & 0 \leq x \leq 2 \\ 3-x ; & 2 \leq x \leq 3 \end{array}\right.

Here we have find out f\; o\; f

Solution :

We have,

              Range of \mathrm{f}=[0,3] \subseteq \text { domain of } \mathrm{f}

\begin{aligned} &\therefore f \circ f(x)=\mathrm{f}(\mathrm{f}(\mathrm{x})) \\ &=\mathrm{f}\left\{\begin{array}{cl} 1+\mathrm{x} ; & 0 \leq x \leq 2 \\ 3-\mathrm{x} ; & 2 \leq x \leq 3 \end{array}\right. \\ &\Rightarrow f \circ f(x)=\left\{\begin{array}{cl} 2+x ; & 0 \leq x \leq 1 \\ 2-x ; & 1 \leq x \leq 2 \\ 4-x ; & 2 \leq x \leq 3 \end{array}\right. \end{aligned}

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