Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma maths Class 12 Chapter Functions Exercise 2.3 Question 12 maths text book solution.

Provide solution for RD Sharma maths Class 12 Chapter Functions Exercise 2.3 Question 12 maths text book solution.

Answers (1)

Answer :

f \circ f(x)=\left\{\begin{array}{ll} 2+x ; & 0 \leq x \leq 1 \\ 2-x ; & 1<x \leq 2 \\ 4-x ; & 2<x \leq 3 \end{array}\right.

Hint : Range of f=[0,3] \subseteq \text { domain of } f.

Given : Given that  f(x)=\left\{\begin{array}{cc} 1+x ; & 0 \leq x \leq 2 \\ 3-x ; & 2 \leq x \leq 3 \end{array}\right.

Here we have find out f\; o\; f

Solution :

We have,

              Range of \mathrm{f}=[0,3] \subseteq \text { domain of } \mathrm{f}

\begin{aligned} &\therefore f \circ f(x)=\mathrm{f}(\mathrm{f}(\mathrm{x})) \\ &=\mathrm{f}\left\{\begin{array}{cl} 1+\mathrm{x} ; & 0 \leq x \leq 2 \\ 3-\mathrm{x} ; & 2 \leq x \leq 3 \end{array}\right. \\ &\Rightarrow f \circ f(x)=\left\{\begin{array}{cl} 2+x ; & 0 \leq x \leq 1 \\ 2-x ; & 1 \leq x \leq 2 \\ 4-x ; & 2 \leq x \leq 3 \end{array}\right. \end{aligned}

Posted by

infoexpert23

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Datesheet 2027 LIVE: Class 10, 12 exam dates soon; sample question papers, time table
anam-khan

CBSE Answer Sheets: CIC tells board to charge photocopying fee as per RTI rules, amend circular
anam-khan

CBSE Class 12 Supplementary Result 2026: Scanned copy, verification, re-evaluation dates announced

Latest Question