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A bucket is in the form of a frustum of a cone and holds 28.490 litres of water. The radii of the top and bottom are 28 cm and 21 cm, respectively. Find the height of the bucket.

Answers (1)

Answer15 cm

Solution

            Given :

                        Volume of bucket = 28.490 liters

                        Radii of the top r_{1}=28cm

                        Radii of the bottom (r_2) = 21cm

            Volume of bucket = 28.490 liters

            Or

            Volume of bucket = 28.490 liters × 1000       (Q1L=1000cm^{3})

                        =28490 cm3

                        \frac{1}{3}\pi h =\left [ r_{1}^2 +r_{2}^2+r_{3}^2\right ]=28490              

                                                (Q volume of frustum of cone \frac{1}{3}\pi h \left [ r_{1}^2 +r_{2}^2+r_{3}^2\right ] )

                        \frac{1}{3} \times 3.14 \times h [(28^2)+(21)^2+28 \times 21]=28490

                        =h[784+441+588]=\frac{28940 \times 3}{3.14}

                          h[1813] = 27219.74

                        h= \frac{27219.74}{1813}=15

                        h = 15 cm

            Hence the height of the bucket is 15 cm.

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