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  • A mason constructs a wall of dimensions 270cm× 300cm × 350cm with the bricks each of size 22.5cm × 11.25cm × 8.75cm and it is assumed that \frac{1}{8} space is covered by the mortar.

A mason constructs a wall of dimensions 270cm\times 300cm \times 350cm with the bricks each of size 22.5cm \times 11.25cm \times 8.75cm and it is assumed that 1/8space is covered by the mortar. Then the number of bricks used to construct the wall is

(A) 11100
(B) 11200
(C) 11000
(D) 11300

Answers (1)

Answer(B) 11200

Solution.
Length of wall = 270 cm
Breadth = 300 cm
Height = 350 cm
Volume =l\times b\times h
    =270\times 300\times 350=28350000cm^{3}
Length of brick = 22.5 cm
Breadth = 11.25 cm
Height = 8.75 cm
Volume =l\times b\times h
    = 22.5 \times 11.25 \times 8.75 = 2214.84375cm^{3}
1/8 Space is covered by mortar (given)
Remaining space

 =\frac{Volume of wall}{8}
 =\frac{28350000}{8}=3543750cm^{3}

\text{Surface constructed} = 28350000 - 3543750 = 24806250cm^{3}
\text{Number of bricks used = }\frac{surface contracted}{volumeof brick}
\Rightarrow \frac{24806250}{2214.84375}=11200

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