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  • A mason constructs a wall of dimensions 270cm× 300cm × 350cm with the bricks each of size 22.5cm × 11.25cm × 8.75cm and it is assumed that \frac{1}{8} space is covered by the mortar.

A mason constructs a wall of dimensions 270cm\times 300cm \times 350cm with the bricks each of size 22.5cm \times 11.25cm \times 8.75cm and it is assumed that 1/8space is covered by the mortar. Then the number of bricks used to construct the wall is

(A) 11100
(B) 11200
(C) 11000
(D) 11300

Answers (1)

best_answer

Answer(B) 11200

Solution.
Length of wall = 270 cm
Breadth = 300 cm
Height = 350 cm
Volume =l\times b\times h
    =270\times 300\times 350=28350000cm^{3}
Length of brick = 22.5 cm
Breadth = 11.25 cm
Height = 8.75 cm
Volume =l\times b\times h
    = 22.5 \times 11.25 \times 8.75 = 2214.84375cm^{3}
1/8 Space is covered by mortar (given)
Remaining space

 =\frac{Volume of wall}{8}
 =\frac{28350000}{8}=3543750cm^{3}

\text{Surface constructed} = 28350000 - 3543750 = 24806250cm^{3}
\text{Number of bricks used = }\frac{surface contracted}{volumeof brick}
\Rightarrow \frac{24806250}{2214.84375}=11200

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