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Water is flowing at the rate of 15 km/h through a pipe of diameter 14 cm into a cuboidal pond which is 50 m long and 44 m wide. In what time will the level of water in pond rise by 21 cm?

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Answer 2 hours


            Length of cuboidal pond = 50m

            Breadth = 44 m

           Height=21 cm =\frac{21}{100}m

         Volume=l \times b \times h

                        =50 \times 44 \times \frac{21}{100}

            Speed of water = 15 km per hour = 15000 m

      \text{ The diameter of the cylindrical pipe }=14 cm =\frac{14}{100}m

  Radius =\frac{7}{100}m

  Volume=\pi r^2 h           

   =\frac{22}{7}\times \frac{7}{100}\times \frac{7}{100}\times 15000 = 213m^3

      \text{ Time required}=\frac{\text{volume of cuboid pond}}{\text{volume of cylindrical pipe}}


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