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  • The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is (A) 4950 cm^2

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

(A) 4950 cm2               (B) 4951 cm2               (C) 4952 cm2               (D) 4953 cm2

Answers (1)

Answer (A) 4950 cm2 

Solution

            Slant height of a bucket = 45 cm

            Top radius =r_{1}=28cm

            Bottom radius =r_{2}=7cm

            Curved surface area of bucket is =\pi l(r_{1}+r_{2})

                        =\frac{22}{7}\times 45 \times (28+7)

                        =\frac{22}{7}\times 45 \times 35

                        =4950cm^{2}

           

 

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infoexpert21

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