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  • The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is

(A) 4950 cm^{2}
(B) 4951 cm^{2}
(C) 4952 cm^{2}
(D) 4953 cm^{2}

Answers (1)

The slant height of a bucket = 45 cm
Top radius =r_{1}=28cm
Bottom radius =r_{2}=7cm
The curved surface area of the bucket is

                                    =\pi l(r_{1}+r_{2})
                                    =\frac{22}{7}\times 45 \times (28+7)
                                   =\frac{22}{7}\times 45 \times 35
                                   =4950cm^{2}

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infoexpert26

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