#### A rectangular water tank of base 11 m × 6 m contains water upto a height of 5 m. If the water in the tank is transferred to a cylindrical tank of radius 3.5 m, find the height of the water level in the tank.

Solution

Length of cuboid = 11m

Height = 5m

$Volume=1\times b\times h$

$=11\times6\times5 = 330m^3$

Radius of cylindrical tank = 3.5m

Let height = h

$\text{Volume }\pi r^2 h = \pi (3.5)^2 h$

To find the height of water level

Volume of cuboid = volume of cylindrical tank

$= 330= \pi (3.5)^2 h$

$h = \frac{330\times7\times100}{22\times35\times35} = \frac{600}{70} = 8.579m$