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How many cubic centimetres of iron is required to construct an open box whose external dimensions are 36 cm, 25 cm and 16.5 cm provided the thickness of the iron is 1.5 cm. If one cubic cm of iron weighs 7.5 g, find the weight of the box.

Answers (1)

Answer 37867.5g or 37.867 kg

Solution

External Length = 36 cm

Breadth = 25 cm

Height = 16.5 cm

Volume 1\times b\times h

  = 36 × 25 × 16.5  

= 14850 cm^3

Thickness of iron = 1.5 cm

Internal length =36 -1.5-1.5    {subtract border from both sides}

= 33 cm

Breadth = 25-1.5-1.5 = 22cm

Height 16.5-1.5-1.5=13cm

Internal volume 1\times b\times h

33\times22\times13.5 = 9801cm^3

Volume of iron = external volume – internal volume

=14850-9801=5049cm^3

Weight of one cubic cm of iron = 7.5 g

 \text{Weight of 5049 cm3 of iron }=5049\times7.5 = 37867.5g

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