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If the current I through a resistor is increased by 100% (assume that temperature remains unchanged), the increase in power dissipated will be

(a) 100 % (b) 200 %

(c) 300 % (d) 400 %

Answers (1)

Answer: (c)

Solution:

Power, P=I²R

Case 1, P₁=I²R

Case 2, P₂=(2I)²R=(4I)²R

Power dissipated = P₂-P₁

=4I²R-I²R

=3I²R

So percentage increase from initial power

$\frac{3I^{2}R}{I^{2}R}\times 100=300$ %

Therefore, option (c) is correct.

Posted by

infoexpert24

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