In an electrical circuit two resistors of 2 Ω and 4 Ω respectively are connected in series to a 6 V battery. The heat dissipated by the 4 Ω resistor in 5 s will be
(a) 5 J
(b) 10 J
(c) 20 J
(d) 30 J
Answer: (c)
Solution:
Given resistors are are connected in series
Equivalent Resistance =
Voltage = 6V
Current in the resistor = V/R = 6/6 = 1 A
Heat dissipated in resistor = I2Rt=12×4×5=20J
Therefore, option (c) is correct.