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Is 0 a term of the AP: 31, 28, 25, ...? Justify your answer.

Answers (1)

Answer.          [False]

Solution.        

Here he given series is 31, 28, 25, …….

\\a = 31\\ d = a\textsubscript{2}- a\textsubscript{1} = 28 - 31= - 3\\ $ If 0 is a term of this A.P then value of n must be a positive integer.\\ $a\textsubscript{n} = a + (n - 1)d\\ 0 = a + (n - 1)d\\ 0 = 31 + (n - 1) (-3)\\ 0 = 31 - 3n + 3\\ 3n = 34\\ n=\frac{34}{3}=11.333. \\

Which is not an integer.

Hence 0 is not a term of this AP.

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