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The first four terms of an AP, whose first term is –2 and the common difference is –2, are

(A) – 2, 0, 2, 4

(B) – 2, 4, – 8, 16

(C) – 2, – 4, – 6, – 8

(D) – 2, – 4, – 8, –16

Answers (1)

Given,

\\a = - 2, d = - 2\\ a + d = - 2 + (-2)\\ = - 4\\ a + 2d = - 2 + 2(-2)\\ =-2 - 4 \\ \ \ = - 6\\ a + 3d = - 2 + 3(-2)\\ =-2 - 6 \\ = - 8\\

 Hence the given AP is -2, -4, -6, - 8

 Hence option (C) is correct.

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