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  • The area of the square that can be inscribed in a circle of radius 8 cm is (A) 256 cm^{2} (B) 128 cm^{2} (C) 64\sqrt{2} cm^{2} (D) 64 cm^{2}

The area of the square that can be inscribed in a circle of radius 8 cm is

(A) 256 cm2                (B) 128 cm2                (C) 64\sqrt{2} cm2             (D) 64 cm2

Answers (1)

 (B) 128 cm2

Solution

Area of square =a2

    

Diagonal of square = Diameter of circle

Diagonal of square =8 \times 2 =16cm

Let the side of the square = a cm

Using Pythagoras theorem in ABC

 (16)2=a2+a2                       

2a2=256

a2=128

Area of square ABCD= a2

                                 =128 cm2

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