The exhibition of various oxidation states by an element is also related to the outer orbital electronic configuration of its atom. Atom(s) having which of the following outermost electronic configurations will exhibit more than one oxidation state in its compounds.
(i) 3s^{1}
(ii) 3d^{1}4s^{2}
(iii) 3d^{2}4s^{2}
(iv) 3s^{2} 3p^{3}

Answers (1)

The answer is the option (iii) and (iv)

Explanation: Atoms having electronic configurations such as in Option (iii) and (iv) will exhibit more than one oxidation state in the compound because in option (iii) electron can be removed from 4s as well as 3d. Similarly, in option (iv) electron can be removed from 3p and 3s both.

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