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Two identical cubes each of volume 64 cm3 are joined together end to end. What is the surface area of the resulting cuboid?

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It is given that volume of cube = 64 cm3

                        a^3=64cm^3          ( Because the volume of cube = a3 )

                        a^3=4^3

                        a=4

            So the side of the two cubes are 4 cm

            The cuboid formed by joining two cubes.

           

            The surface area of the cuboid =2(lb +bh+hl)

                        =2(8 \times 4 + 4 \times + 4 \times 8)

                        =2(8 \times 4 +4 \times 4 + 4 \times 8)

                        =2(32+16 +32)

          =2(80)=160cm^2  

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