#### Two identical cubes each of volume 64 cm3 are joined together end to end. What is the surface area of the resulting cuboid?

It is given that volume of cube = 64 cm3

$a^3=64cm^3$          ( Because the volume of cube = a3 )

$a^3=4^3$

$a=4$

So the side of the two cubes are 4 cm

The cuboid formed by joining two cubes.

The surface area of the cuboid $=2(lb +bh+hl)$

$=2(8 \times 4 + 4 \times + 4 \times 8)$

$=2(8 \times 4 +4 \times 4 + 4 \times 8)$

$=2(32+16 +32)$

$=2(80)=160cm^2$