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#### Water is flowing at the rate of 15 km/h through a pipe of diameter 14 cm into a cuboidal pond which is 50 m long and 44 m wide. In what time will the level of water in pond rise by 21 cm?

Solution

Length of cuboidal pond = 50m

Breadth = 44 m

$Height=21 cm =\frac{21}{100}m$

$Volume=l \times b \times h$

$=50 \times 44 \times \frac{21}{100}$

Speed of water = 15 km per hour = 15000 m

$\text{ The diameter of the cylindrical pipe }=14 cm =\frac{14}{100}m$

$Radius =\frac{7}{100}m$

$Volume=\pi r^2 h$

$=\frac{22}{7}\times \frac{7}{100}\times \frac{7}{100}\times 15000 = 213m^3$

$\text{ Time required}=\frac{\text{volume of cuboid pond}}{\text{volume of cylindrical pipe}}$

$=\frac{462}{231}=2hours$