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  • Explain Solution R.D.Sharma Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 14 maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 14 maths Textbook Solution.

Answers (1)

Answer: 2x^{2}-12x+19=0

Hint: find the slope of the curve

Given: y=\frac{1}{x-3},x\neq 3

Solution: Slope of the line is 2

Slope of the curve is \frac-{1}{\left ( x-3 \right )}^{2}

\begin{aligned} &\Rightarrow-\frac{1}{(x-3)^{2}}=2 \\ &\Rightarrow 2(x-3)^{2}=-1 \\ &\Rightarrow 2\left(x^{2}-6 x+9\right)=-1 \\ &\Rightarrow 2 x^{2}-12 x+19=0 \end{aligned}

Which has no real roots b^{2}-4ac< 0

Hence: there is no tangent to the given curve having slope 2.

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