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Provide solution for RD Sharma Class 12 Chapter 15 Tangents and Normals Exercise Multiple Choice Question , Question 28 maths textbook solution. 

Answers (1)

Answer : (b) is the correct option

Hint :

Equation of normal \frac{y-y_{1}}{x-x_{1}}=m(N)

Given : 2 y+x^{2}=3

Solution :

2 y+x^{2}=3                                       (1)

Differentiating equation (1) w.r.t y

\begin{aligned} &2+2 x \frac{d x}{d y}=0 \\ &\frac{d x}{d y}=-\frac{1}{x} \end{aligned}

\begin{aligned} &-\frac{d x}{d y}=\frac{1}{x} \\ &{\left[-\frac{d y}{d x}\right]_{(1,1)}=\frac{1}{1}=1=m(N)} \end{aligned}

Equation of the normal at the point (1,1) is \frac{y-1}{x-1}=m(N)

\begin{aligned} &\frac{y-1}{x-1}=1 \\ &y-1=x-1 \\ &x-y=0 \end{aligned}

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