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  • Provide solution for RD Sharma Class 12 Chapter 15 Tangents and Normals Exercise Multiple Choice Question, Question 28 maths textbook solution.

Provide solution for RD Sharma Class 12 Chapter 15 Tangents and Normals Exercise Multiple Choice Question , Question 28 maths textbook solution. 

Answers (1)

Answer : (b) is the correct option

Hint :

Equation of normal \frac{y-y_{1}}{x-x_{1}}=m(N)

Given : 2 y+x^{2}=3

Solution :

2 y+x^{2}=3                                       (1)

Differentiating equation (1) w.r.t y

\begin{aligned} &2+2 x \frac{d x}{d y}=0 \\ &\frac{d x}{d y}=-\frac{1}{x} \end{aligned}

\begin{aligned} &-\frac{d x}{d y}=\frac{1}{x} \\ &{\left[-\frac{d y}{d x}\right]_{(1,1)}=\frac{1}{1}=1=m(N)} \end{aligned}

Equation of the normal at the point (1,1) is \frac{y-1}{x-1}=m(N)

\begin{aligned} &\frac{y-1}{x-1}=1 \\ &y-1=x-1 \\ &x-y=0 \end{aligned}

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