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Provide Solution For R.D.Sharma Maths Class 12 Chapter 15 Tangents and Normals Exercise Multiple Choice Questions Question 2 Maths Textbook Solution.

Answers (1)

Answer:

            \left ( d \right )2x=\pi

Hint:

       Use differentiation

Given:

            y=x+\sin \: x\: \cos \: x

Solution:

\begin{aligned} &y=x+\sin x \cos x\\ &=x+\frac{\sin (2 x)}{2}\\ &y^{\prime}=1+\cos (2 x)\\ &\text { Substituting } x=\frac{\pi}{2}\\ &y^{\prime}\left(\frac{\pi}{2}\right)=1+\cos (\pi)\\ &=0 \end{aligned}

Therefore, slope of tangent is 0. this means that the normal is a vertical line of the x=c

Since the point has x-coordinate\frac{\pi }{2} , the equation of the line is

x=\frac{\pi }{2}

2x=\pi is requried

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