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Please Solve R.D.Sharma Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 3 Sub Question 3 Maths Textbook Solution.

Answers (1)

Answer:Equation of tangent,x=0

               Equation  of normal, y=0

HINTS:

 Differentiating the given equation .

GIVEN:

y=x^{2} \text { at }(0,0)

Solution:

\frac{d y}{d x}=2 x

Given (x, y)=(0,0)

Slope of tangent ,

m=\left(\frac{d y}{d x}\right)_{(0,0)}=2(0)=0

Equation of tangent is,

\begin{aligned} &y-y_{1}=m\left(x-x_{1}\right) \\ &\Rightarrow y-0=0(x-0) \\ &\Rightarrow y=0 \end{aligned}

Equation of Normal  is,

\begin{aligned} &\Rightarrow y-y_{1}=-\frac{1}{m}\left(x-x_{1}\right) \\ &\Rightarrow y-0=-\frac{1}{0}(x-0) \\ &\Rightarrow x=0 \end{aligned}

 

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