Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution R.D.Sharma Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 15 maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 15 maths Textbook Solution.

Answers (1)

Answer:  y=\frac{1}{2}

Hint: Differentiate

Given:  y=\frac{1}{x^{2}-2x+3}

Solution:

\begin{aligned} &\frac{d y}{d x}=-\frac{1}{\left(x^{2}-2 x+3\right)^{2}} \times(2 x-2)\\ &\therefore-\frac{(2 x-2)}{\left(x^{2}-2 x+3\right)^{2}}=0 \Rightarrow x=1\\ &\text { when } x=1, y=\frac{1}{2}\\ &\therefore \text { Equation of the line } y-\frac{1}{2}=0(x-1)\\ &y=\frac{1}{2} \Rightarrow 2 y=1 \quad \text { or } \quad 2 y-1=0 \end{aligned}

Posted by

infoexpert21

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE 12th Results LIVE: Class 12 marksheet on cbse.gov.in, DigiLocker soon; OSM system, passing marks
anam-khan

CBSE 12th Result 2026 Date LIVE: Class 12 results at cbse.gov.in soon; how to check on Digilocker, Umang
anam-khan

CBSE 12th Result 2026 Date: Here’s what previous years’ trends indicate

Latest Question