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  • Provide Solution For R.D.Sharma Maths Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 2 Maths Textbook Solution.

Provide Solution For  R.D.Sharma Maths Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 2 Maths Textbook Solution.

Answers (1)

Answer: x+4 y=17

Hint:

We find the slope of tangent  and using relation,

\text { slope of normal }=\frac{-1}{\text { slope }} \text { of tangent. }

Given:

y=2 x^{3}-x^{2}+3 \text { at }(1,4)

Solution:

\left.\frac{d y}{d x}\right|_{1,4]}=\left.\left(6 x^{2}-2 x\right)\right|_{(1,4)}

m=6-2

      \therefore m=4, \text { slope of tangent }

Equation of normal will be

\Rightarrow y-4=-\frac{1}{4}(x-1)

  x+4 y=17

 

 

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