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  • If e is the eccentricity of the ellipse , then x^2/a^ 2+ y^2/b^2 = 1 (a<b) A. b^2 = a^2 (1 – e^2) B. a^2 = b^2 (1 – e^2) C. a^2 = b^2 (e^2 – 1) D. b^2 = a^2 (e^2 – 1)

If e is the eccentricity of the ellipse \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\left ( a<b \right ), then
A. b2 = a2 (1 – e2)
B. a2 = b2 (1 – e2)
C. a2 = b2 (e2 – 1)
D. b2 = a2 (e2 – 1)

Answers (1)

Option (b) is correct.

Given that \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

We know that a2=b2(1-e2)

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infoexpert22

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