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  • Find the equation of the circle having (1, –2) as its centre and passing through3x + y = 14, 2x + 5y = 18

Find the equation of the circle having (1, –2) as its centre and passing through 3x + y = 14, 2x + 5y = 18

Answers (1)

Given lines are

3x+y=14 and 2x+5y=18

Solving these equations we get point of intersection of the lines as A (4,2)

Radius= \sqrt{\left (4-1 \right )^{2}+\left (2-(-2 \right )^{2}}=\sqrt{9+16}=5

So, equation of the required circle is: 

(x-1)2+(y+2)2=52

x2+y2-2x+4y-20=0

Posted by

infoexpert22

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