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If the latus rectum of an ellipse is equal to half of minor axis, then find its eccentricity.

Answers (1)

Consider the equation of the ellipse as \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

It is given that length of latus rectum = Half of minor axis

\frac{2b^{2}}{a}=b

a=2b

b2=a2(1-e2)

b2=4b2(1-e2)

1-e2=1/4

e2=3/4

e=\frac{\sqrt{3}}{2}

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