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  • The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is A. x^2 + y^2 = 9a^2 B. x^2 + y^2 = 16a^2 C. x^2 + y^2 = 4a^2 D. x^2 + y^2 = a^2

The equation of a circle with origin as centre and passing through the vertices of an equilateral triangle whose median is of length 3a is
A. x2 + y2 = 9a2
B. x2 + y2 = 16a2
C.x2 + y2 = 4a2
D. x2 + y2 = a2

Answers (1)

Option (C)

median length=3a

Radius of circle=2/3*median length=2a

Equation of circle

x2+y2=4a2

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infoexpert22

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