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  • The shortest distance from the point (2, –7) to the circle x square plus 7=y square minus 14x minus 10y minus 151equal to 0 is equal to 5.

The shortest distance from the point (2, –7) to the circle x2 + y2 – 14x – 10y – 151 = 0 is equal to 5.

Answers (1)

False

\text { Centre } \equiv C(7,5) \\

$ Radius $=\sqrt{49+25+151}=\sqrt{225}=15

\\$Distance between the point $P(2,-7)$ and centre $$ =\sqrt{(2-7)^{2}+(-7-5)^{2}}=\sqrt{169}=13

\text {The shortest distance of point } \mathrm{P} \text{ from the circle} =|13-15|=2

 

Posted by

Ravindra Pindel

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