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In Fig., if \angleD = \angleC, then is it true that \Delta ADE \sim \Delta ACB ? Why?

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Answer : [True]

In \Delta ADE and \Delta ACB

\angle D=\angle C        (given)

\angle A = \angle A      (common angle)

And we know that if two angles of one triangle are equal to the two angles of another triangle, then the two triangles are similar by AA similarity criteria.

\therefore   \Delta ADE \sim \Delta ACB         {by AA similarity criterion}

Hence the given statement is true.

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