Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain Solution for RD Sharma Maths Class 12 Chapter 6 Adjoint and inverse of a Matrix Exercise very short answer type Question 19 maths textbook solution

Explain Solution for RD Sharma Maths Class 12 Chapter 6 Adjoint and inverse of a Matrix Exercise very short answer type Question 19 maths textbook solution

Answers (1)

VSQ : 19

Answer : \frac{1}{19}

Given : A=\left[\begin{array}{cc} 2 & 3 \\ 5 & -2 \end{array}\right] \& A^{-1}=K A

Hint : Find A^{-1} and put it in equation and then compare it.

Solution : $$ A=\left[\begin{array}{cc} 2 & 3 \\ 5 & -2 \end{array}\right]

$$ \begin{aligned} &|A|=-4-15 \\ &=-19 \\ &|A| \neq 0 \\ &A^{-1} \text { exists } \\ &A^{-1}=\frac{\operatorname{adj} A}{|A|} \end{aligned}

$$ \begin{aligned} &=\frac{-1}{19}\left[\begin{array}{cc} -2 & -3 \\ -5 & 2 \end{array}\right]\\ &=\frac{-1}{19}\left[\begin{array}{cc} 2 & 3 \\ 5 & -2 \end{array}\right]\\ &\text { Now } \mathrm{A}^{-1}=K A\\ &\frac{1}{19}\left[\begin{array}{cc} 2 & 3 \\ 5 & -2 \end{array}\right]=K\left[\begin{array}{cc} 2 & 3 \\ 5 & -2 \end{array}\right]\\ &\text { On comparing }\\ &\mathrm{K}=\frac{1}{19} \end{aligned}

Posted by

Infoexpert

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Time Table 2025 Live: UP Board exams from February 24; CBSE, BSEB date sheet soon
anam-khan

CBSE Date Sheet 2025 Live: Class 10, 12 board exam dates soon; syllabus, sample papers
anam-khan

Extra time in CBSE exams for students with type 1 diabetes: Kerala SHRC seeks report on plea

Latest Question