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  • Explain Solution for RD Sharma Maths Class 12 Chapter 6 Adjoint and inverse of a Matrix Exercise very short answer type Question 22 maths textbook solution

Explain Solution for RD Sharma Maths Class 12 Chapter 6 Adjoint and inverse of a Matrix Exercise very short answer type Question 22 maths textbook solution

Answers (1)

VSQ : 22

Answer : \left[\begin{array}{cc} 5 & 2 \\ 7 & 3 \end{array}\right]

Given : \left[\begin{array}{cc} 3 & -2 \\ -7 & 5 \end{array}\right]

Hint : you must know about how to find inverse of a matrix

Solution : \left[\begin{array}{cc} 3 & -2 \\ -7 & 5 \end{array}\right]

$$ \begin{aligned} &c_{11}=5, c_{12}=7, c_{21}=2, c_{22}=3 \\ &=\frac{1}{1}\left[\begin{array}{cc} 5 & 7 \\ 2 & 3 \end{array}\right] \\ &=\left[\begin{array}{cc} 5 & 7 \\ 2 & 3 \end{array}\right] \end{aligned} 

Now transpose it, we get

 

 

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