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  • Explain Solution for RD Sharma Maths Class 12 Chapter 6 Adjoint and inverse of a Matrix Exercise very short answer type Question 25 maths textbook solution

Explain Solution for RD Sharma Maths Class 12 Chapter 6 Adjoint and inverse of a Matrix Exercise very short answer type Question 25 maths textbook solution

Answers (1)

VSQ:25

Answer : \left[\begin{array}{cc}d & -b \\ -c & a\end{array}\right]

Given : A=\left[\begin{array}{cc}a & b \\ c & d\end{array}\right] &B=\left[\begin{array}{cc}1 & 0 \\ 0 & 1\end{array}\right]

Hint : find adj A and find adj B and then use the formula of adj (AB)

Solution : A=\left[\begin{array}{cc}a & b \\ c & d\end{array}\right]

adj A=\left[\begin{array}{cc}d & -b \\ -c & a\end{array}\right]

B=\left[\begin{array}{cc}1 & 0 \\ 0 & 1\end{array}\right]

adj B=\left[\begin{array}{cc}1 & 0 \\ 0 & 1\end{array}\right]

Now we know that 

adj(AB) =adj(B)adj(A)

=\left[\begin{array}{cc}1 & 0 \\ 0 & 1\end{array}\right]\left[\begin{array}{cc}d & -b \\ -c & a\end{array}\right]

adj\left ( AB \right )=\left[\begin{array}{cc}d & -b \\ -c & a\end{array}\right]

 

 

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