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  • Explain Solution for RD Sharma Maths Class 12 Chapter 6 Adjoint and inverse of a Matrix Exercise very short answer type Question 8 maths textbook solution

Explain Solution for RD Sharma Maths Class 12 Chapter 6 Adjoint and inverse of a Matrix Exercise very short answer type Question 8 maths textbook solution

Answers (1)

VSQ :8

Answer : adj\left ( AB \right )= adjB.adjA

Given : 

Hint : use the formula adj\left ( AB \right )= adjB.adjA

Solution :  adj\left ( AB \right )= adjB.adjA

\begin{aligned} &=\left[\begin{array}{cc} 1 & -2 \\ -3 & 1 \end{array}\right]\left[\begin{array}{cc} 2 & 3 \\ 4 & -1 \end{array}\right] \\ &=\left[\begin{array}{cc} 2-8 & 3+2 \\ -6+4 & -9-1 \end{array}\right] \end{aligned}

\left ( adjAB \right )=\left[\begin{array}{cc} -6 & 5 \\ -2 & -10 \end{array}\right]

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