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Need solution for RD Sharma maths class 12 chapter 10 Differentiation exercise Very short answers question 7

Answers (1)

Answer:

The answer of the given question will be 1.

Given:

If   \sin ^{-1}(\sin x),-\frac{\pi}{2} \leq x \leq \frac{\pi}{2}   then write the value of \frac{d y}{d x} \text { for } x \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]

Hint:

x \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]

Solution:  

\begin{aligned} &\sin ^{-1}(\sin x)=x, x \in\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] \\\\ &\Rightarrow \frac{d y}{d x}=\frac{d}{d x}(x)=1 \\\\ &\therefore \frac{d y}{d x}=1 \end{aligned}

So the answer will be 1.

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