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explain solution RD Sharma class 12 chapter Differentiation exercise 10.2 question 4 maths

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Answer:  \frac{1}{x} \cos (\log x)

Hint: You must know the rules of solving derivative of logarithm function.

Given:  \sin (\log x)


y=\sin (\log x)

Differentiating with respect to x,

\begin{aligned} &\frac{d y}{d x}=\frac{d}{d x} \sin (\log x) \\ &\frac{d y}{d x}=\cos (\log x) \frac{d}{d x}(\log x) \end{aligned}            [ using chain rule]              

\frac{d y}{d x}=\frac{1}{x} \cos (\log x)                                                                                                        


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