Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma maths class 12 chapter Differentiation exercise 10.5 question 18 sub question (vi)

Need solution for RD Sharma maths class 12 chapter Differentiation exercise 10.5 question 18 sub question (vi)

Answers (1)

Answer: e^{\sin x} \cos x+(\tan x)^{x} \cdot\left[\log (\tan x)+\frac{x \sec ^{2} x}{\tan x}\right]

Hint: Diff by e^{\sin x}

Given: e^{\sin x}+(\tan x)^{x}

Solution:  y=e^{\sin x}+(\tan x)^{x}

Let   z=(\tan x)^{x}

Take log on both sides

        \log z=x \log \tan x

Diff w.r.t x

        \frac{1}{z} \frac{d z}{d x}=\log \tan x+\frac{x \sec ^{2} x}{\tan x}

Thus

        \frac{d y}{d x}=e^{\sin x} \cos x+(\tan x)^{x} \cdot\left[\log (\tan x)+\frac{x \sec ^{2} x}{\tan x}\right]

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

When will CBSE Class 12 results 2025 be declared? Last two years' trends
anam-khan

CBSE Class 10, 12 board exams 2025 from April 7 to 11 for sports students
anam-khan

CBSE Class 12 history paper 2025 moderately difficult, tested students’ understanding

Latest Question