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Please solve RD Sharma class 12 chapter Differentiation exercise 10.2 question 1 maths textbook solution

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Answer: 3 \cos (3 x+5)

Hint: You must know the values of solving derivative problems.

Given:  \sin (3 x+5)

Solution: \sin (3 x+5)

Let : y=\sin (3 x+5)


Differentiating with respect to x,

\frac{d y}{d x}=\frac{d}{d x}[\sin (3 x+5)]

\frac{d y}{d x}=\cos (3 x+5) \frac{d}{d x}(3 x+5)                                [using chain rule]

\begin{aligned} &\frac{d y}{d x}=\cos (3 x+5) \times(3) \\ &\frac{d y}{d x}=3 \cos (3 x+5) \end{aligned}



\begin{aligned} &\frac{d y}{d x}=\frac{d}{d x}[\sin (3 x+5)] \\ &\frac{d y}{d x}=3 \cos (3 x+5) \end{aligned}

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