Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Need solution for RD Sharma maths class 12 chapter Differentiation exercise 10.5 question 23

Need solution for RD Sharma maths class 12 chapter Differentiation exercise 10.5 question 23

Answers (1)

Answer: \frac{d y}{d x}=e^{3 x} \cdot \sin 4 x .2 x\left[e^{3 x} \cdot \sin 4 x \cdot 2^{x}(3+4 \cot 4 x+\ln 2)\right]

Hint: Differentiate the equation taking log on both sides

Given: y=e^{3 x} \cdot \sin 4 x \cdot 2^{x}

Solution:  

                                            [\because \log A B=\log A+\log B]

        \ln y=\ln e^{3 x}+\ln \sin 4 x+\ln 2^{x}

Diff w.r.t x

        \frac{1}{y} \frac{d y}{d x}=\frac{1}{e^{3 x}} \cdot \cdot e^{3 x} \cdot 3+\frac{\cos 4 x}{\sin 4 x} \cdot 4+\ln 2

        \frac{d y}{d x}=e^{3 x} \cdot \sin 4 x .2 x\left[e^{3 x} \cdot \sin 4 x .2 x(3+4 \cot 4 x+\ln 2)\right]

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2027 LIVE: 10th, 12th time table soon on cbse.gov.in; sample papers, grading system
anam-khan

CBSE Date Sheet 2027 LIVE: Class 10, 12 board exam schedule soon; passing marks, paper pattern
anam-khan

CBSE Class 12 West Asia special exam date sheet 2026 out; admit cards from October 12

Latest Question