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Provide Solutio for RD Sharma Class 12 Chapter Continuity Exercise 8.1 Subquestion (iii) Question 10

Answers (1)

Answer:

                Continuous

Hint:

 For a function to be continuous at a point, its LHL RHL and value at that point should be equal.

Solution:

Given,

f(x)=\left(\begin{array}{c} (x-a) \sin \left(\frac{1}{x-a}\right), \text { if } x \neq a \\\\ 0, \text { if } x=a \end{array}\right)

Putting  x-a=y , we get

\begin{aligned} &\lim _{x \rightarrow a}(x-a) \sin \left(\frac{1}{x-a}\right)=\lim _{y \rightarrow 0} y \sin \left(\frac{1}{y}\right)=\lim _{y \rightarrow 0} y \lim _{y \rightarrow 0} \sin \left(\frac{1}{y}\right)=0 \times \lim _{y \rightarrow 0} \sin \left(\frac{1}{y}\right)=0 \\\\ &\lim _{x \rightarrow a} f(x)=f(a)=0 \end{aligned}

Hence,  f\left ( x \right ) is continuous at x=a.

 

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