Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for rd sharma class 12 chapter 6 Adjoint and Inverse of Matrix excercise 6.2 question 5

Provide solution for rd sharma class 12 chapter 6 Adjoint and Inverse of Matrix excercise 6 point 2 question 5

Answers (1)

best_answer

    

Answer: \left[\begin{array}{cc} 7 & -10 \\ -2 & 3 \end{array}\right]

Hint: Here, we use the concept of matrix inverse using elementary row operation

Given: A=\left[\begin{array}{cc} 3 & 10 \\ 2 & 7 \end{array}\right]

Solution: Let A=\left[\begin{array}{cc} 3 & 10 \\ 2 & 7 \end{array}\right]

                   A = IA

                    A=\left[\begin{array}{cc} 3 & 10 \\ 2 & 7 \end{array}\right], I=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]

                    \Rightarrow\left[\begin{array}{cc} 3 & 10 \\ 2 & 7 \end{array}\right]=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right] A

Applying R_{1} \rightarrow \frac{1}{3} R_{1}

              \Rightarrow\left[\begin{array}{ll} 1 & \frac{10}{3} \\ 2 & 7 \end{array}\right]=\left[\begin{array}{ll} \frac{1}{3} & 0 \\ 0 & 1 \end{array}\right] A

Applying  R_{2} \rightarrow R_{2}-2 R_{1}

            \Rightarrow\left[\begin{array}{ll} 1 & \frac{10}{3} \\ 0 & \frac{1}{3} \end{array}\right]=\left[\begin{array}{cc} \frac{1}{3} & 0 \\ \frac{-2}{3} & 1 \end{array}\right] A

             

Applying R_2\rightarrow 3R_2

              \Rightarrow\left[\begin{array}{ll} 1 & \frac{10}{3} \\ 0 & 1 \end{array}\right]=\left[\begin{array}{cc} \frac{1}{3} & 0 \\ -2 & 3 \end{array}\right] A

Applying R_{1} \rightarrow R_{1}-\frac{10}{3} R_{2}

              \Rightarrow\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]=\left[\begin{array}{cc} 7 & -10 \\ -2 & 3 \end{array}\right]

 

Hence, \left[\begin{array}{cc} 7 & -10 \\ -2 & 3 \end{array}\right]

Posted by

Infoexpert

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

What after CBSE Class 12 results 2024? From CUET UG to JEE Advanced, all you need to know
anam-khan

CBSE Results 2024: Maximum full marks scorers in Class 10 mathematics, 12th painting
anam-khan

CBSE 10th, 12th Results 2024: Not happy with scores? Here’s how to apply for revaluation

Latest Question