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  • A carpenter had a board which measured 3m × 2m. She cut out a rectangular piece of 250cm × 90cm. What is the ratio of the area of cut out piece and the remaining piece?

A carpenter had a board which measured 3m × 2m. She cut out a rectangular piece of 250cm × 90cm. What is the ratio of the area of cut out piece and the remaining piece?

Answers (1)

Given: Area of the board = 3 \mathrm{~m} \times 2 \mathrm{~m} = 6 \mathrm{~m}^2
Area of cut out piece = 250 \mathrm{~cm} \times 90 \mathrm{~cm} =2.2500 \mathrm{~m}^{2}
Area of remaining piece = =(6-2.25) = 3.75 \mathrm{m}^{2}

Ratio of the area of cut out piece and the remaining piece=

\frac{\text { The area of cut out piece }}{\text { The area of remaining piece }} = \frac{2.25 \mathrm{~m}^{2}}{3.75 \mathrm{m}^{2}}=\frac{3}{5}=3: 5

Posted by

Ravindra Pindel

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