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  • Find the missing number in the box -- in each of the proportions: \frac{16}{36}=\frac{--}{63}=\frac{36}{--}=\frac{--}{117}

Find the missing number in the box -- in each of the proportions:

\frac{16}{36}=\frac{--}{63}=\frac{36}{--}=\frac{--}{117}

Answers (1)

Assume the missing number are x, y,z .

\frac{16}{36}=\frac{x}{63}=\frac{36}{y}=\frac{z}{117}
\frac{x}{63} = \frac{16}{36}

x =\frac{16}{36} \times 63 = 28

\frac{36}{y} = \frac{16}{36}

y =\frac{36}{16} \times 36 = 81

\frac{z}{117} = \frac{16}{36}

z =\frac{16}{36} \times 117 = 52

Hence, the missing number in box are 28, 81, 52.

Posted by

Ravindra Pindel

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