Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Length and breadth of the floor of a room are 5m and 3m, respectively. Forty tiles, each with area \frac{1}{16}m^{2} are used to cover the floor partially. Find the ratio of the tiled and the non tiled portion of the floor.

Length and breadth of the floor of a room are 5m and 3m, respectively. Forty tiles, each with area \frac{1}{16}m^{2} are used to cover the floor partially. Find the ratio of the tiled and the non tiled portion of the floor.

Answers (1)

Given: Length of the floor = 5 m

Breadth of the floor = 3 m

Total area of the floor = 5 \mathrm{~m} \times 3 \mathrm{~m} = 15 \text{m}^2

Area of one tile = \frac{1}{16} \text{m}^2

Number of tiles = 40

Area covered with tiles = 40 \times \frac{1}{16} \mathrm{~m}^{2}=\frac{5}{2} \mathrm{~m}^{2}
The non tiled area = \left[15-\frac{5}{2}\right] = \frac{25}{2} \mathrm{m}^{2}

Ratio of the tiled and the non tiled portion of the floor.= \frac{\text { Tiled area }}{\text { Non tiled area }} = \frac{\frac{5}{2}}{\frac{25}{2}} = \frac{1}{5}

Posted by

Ravindra Pindel

View full answer

Similar Questions

Latest Question