#### Length and breadth of the floor of a room are 5m and 3m, respectively. Forty tiles, each with area $\frac{1}{16}m^{2}$ are used to cover the floor partially. Find the ratio of the tiled and the non tiled portion of the floor.

Given: Length of the floor = 5 m

Breadth of the floor = 3 m

Total area of the floor = $5 \mathrm{~m} \times 3 \mathrm{~m} = 15 \text{m}^2$

Area of one tile = $\frac{1}{16} \text{m}^2$

Number of tiles = 40

Area covered with tiles = $40 \times \frac{1}{16} \mathrm{~m}^{2}=\frac{5}{2} \mathrm{~m}^{2}$
The non tiled area = $\left[15-\frac{5}{2}\right] = \frac{25}{2} \mathrm{m}^{2}$

Ratio of the tiled and the non tiled portion of the floor.= $\frac{\text { Tiled area }}{\text { Non tiled area }} = \frac{\frac{5}{2}}{\frac{25}{2}} = \frac{1}{5}$