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A milk container of height 16 cm is made of metal sheet in the form of a frustum of a cone with radii of its lower and upper ends as 8 cm and 20 cm respectively. Find the cost of milk at the rate of Rs. 22 per litre which the container can hold.

Answers (1)

Answer 230.10 Rs.

Solution

            Upper radius of frustum of cone (R) = 20cm

            Lower radius of frustum of cone r = 8cm

            Height (h)= 16cm

            Volume \frac{\pi h}{3}[R^2+r^2+Rr]

                        \frac{22 \times 16}{7 \times 3}(20^2+8^2+20 \times 8)

                        \frac{22 \times 16}{21}(400 + 64+160)

                        

                        \frac{22 \times 16}{21}(624)

                        \frac{22 \times 16\times 208}{7}=10459.428 m^3

                                                  = 10.459 liter

            Cost of 1 liter milk = 22 Rs.

            Cost of 10.459 liter milk 22 \times 10.459

                     =   2301.10 Rs

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