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A wall 24 m long, 0.4 m thick and 6 m high is constructed with the bricks each of dimensions 25 cm \times 16 cm \times 10 cm. If the mortar occupies1/10 th of the volume of the wall, then find the number of bricks used in constructing the wall.

Answers (1)

Answer 12960

Solution

            Length of wall =24 m =24 \times 100 =2400 cm         ( because 1m = 100cm )

            Breadth of wall =0.4m =0.4 \times 100 =40 cm

            Height of wall = 6m = 6 \times 100 = 600cm

            The volume of wall = length × breadth × height

                        =2400 \times 40 \times 600

                        =5760000cm^3

     \text{ Mortar occupied}=\frac{5760000}{10} =5760000cm^3

           Remaining volume = 57600000 – 5760000 = 51840000 cm3

            Length of brick = 25 cm

            Breadth of brick = 16cm

            Height of brick = 10cm

            Volume of brick = length × breadth × height

                                    = 25 × 16 × 10 = 4000 cm3

            \text{Number of bricks}=\left [ \frac{\text{remaining volume} }{\text {volume of brick}} \right ]=\frac{5184000}{4000}=12960                      

            Hence the number of bricks is 12960        

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