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  • Explain solution for RD Sharma Class 12 Chapter 15 Tangent and Normals Exercise Very short Answers Question 19 for maths textbook solution.

Explain solution for RD Sharma Class 12 Chapter 15 Tangent and Normals Exercise Very short Answers Question 19 for maths textbook solution.

Answers (1)

Answer : 0

Hint :

Simply we will find \frac{dy}{dx} at x = \frac{\pi }{6}

Given:

Given curve,

y=2 \sin ^{2} 3 x

We have to find the slope of the tangent to the given curve at x = \frac{\pi }{6}

Solution :

y=2 \sin ^{2} 3 x

Differentiating both sides with respect to x, we get

\begin{aligned} &\frac{d y}{d x}=2 \times 2 \sin (3 x) \times \cos (3 x) \times 3 \\ &\Rightarrow \quad\left(\frac{d y}{d x}\right)_{x=\frac{\pi}{6}}=12 \times \sin \left(\frac{\pi}{2}\right) \times \cos \left(\frac{\pi}{2}\right) \end{aligned}

                   =12\times1\times0

\left(\frac{d y}{d x}\right)=0

Hence the slope of tangent = 0

Posted by

infoexpert21

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