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  • Explain solution for RD Sharma maths Class 12 Chapter 15 Tangents and Normals Exercise Multiple Choice Question ,Question 33 maths textbook solution.

Explain solution for RD Sharma maths Class 12 Chapter 15 Tangents and Normals Exercise Multiple Choice Question, Question 33 maths textbook solution.

Answers (1)

Answer : (b) is the correct option

Hint : Equation of tangent y-y_{1}=m\left(x-x_{1}\right)

Given : y=e^{2 x}

Solution :

y=e^{2 x}                                                (1)

Differentiating (1) w.r.t x, we get

\begin{aligned} &\frac{d y}{d x}=2 e^{2 x} \\ &\left.\frac{d y}{d x}\right|_{x=0}=2 e^{0}=2 \end{aligned}

Equation of the tangent at the point (0, 1) and having the slope 2 is

\begin{aligned} &y-1=2(x-0) \\ &y-1=2 x \\ &y=2 x+1 \end{aligned}

Since it (2) meets in x-axis

\therefore y=0

Putting y=0 in (2)

0=2 x+1 \Rightarrow x=-\frac{1}{2}

\therefore The tangent meets at the point  P\left(\frac{-1}{2}, 0\right)

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