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  • Explain Solution R.D.Sharma Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 15 maths Textbook Solution.

Explain Solution R.D.Sharma Class 12 Chapter 15 Tangents and Normals Exercise 15.2 Question 15 maths Textbook Solution.

Answers (1)

Answer:  y=\frac{1}{2}

Hint: Differentiate

Given:  y=\frac{1}{x^{2}-2x+3}

Solution:

\begin{aligned} &\frac{d y}{d x}=-\frac{1}{\left(x^{2}-2 x+3\right)^{2}} \times(2 x-2)\\ &\therefore-\frac{(2 x-2)}{\left(x^{2}-2 x+3\right)^{2}}=0 \Rightarrow x=1\\ &\text { when } x=1, y=\frac{1}{2}\\ &\therefore \text { Equation of the line } y-\frac{1}{2}=0(x-1)\\ &y=\frac{1}{2} \Rightarrow 2 y=1 \quad \text { or } \quad 2 y-1=0 \end{aligned}

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